i(z^2)+2z-1=0

Solution for i(z^2)+2z-1=0 equation:

Simplifying
i(z2) + 2z + -1 = 0

Multiply i * z2
iz2 + 2z + -1 = 0

Reorder the terms:
-1 + iz2 + 2z = 0

Solving
-1 + iz2 + 2z = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + iz2 + 1 + 2z = 0 + 1

Reorder the terms:
-1 + 1 + iz2 + 2z = 0 + 1

Combine like terms: -1 + 1 = 0
0 + iz2 + 2z = 0 + 1
iz2 + 2z = 0 + 1

Combine like terms: 0 + 1 = 1
iz2 + 2z = 1

Add '-2z' to each side of the equation.
iz2 + 2z + -2z = 1 + -2z

Combine like terms: 2z + -2z = 0
iz2 + 0 = 1 + -2z
iz2 = 1 + -2z

Divide each side by 'z2'.
i = z-2 + -2z-1

Simplifying
i = z-2 + -2z-1